Javascript ES6: Destructuring with default values
This is a short, but very useful code snippet for destructuring variables with default values (if the value is undefined). Very useful snippet for avoiding errors caused by undefined variables. In the following example, the options object is being destructured. const { valFirst = 1, valSecond = "hello", valThird = false } = options; If a destructured value doesn't exist within the object, it will be assigned a default value. If it does exist within the object, it will be assig
This is a short, but very useful code snippet for destructuring variables with default values (if the value is undefined). Very useful snippet for avoiding errors caused by undefined
variables.
In the following example, the options
object is being destructured.
const {
valFirst = 1,
valSecond = "hello",
valThird = false
} = options;
If a destructured value doesn't exist within the object, it will be assigned a default value. If it does exist within the object, it will be assigned the value from the object.
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